/Matrix [1 0 0 1 0 0] ET ET Q >> /Font << /Subtype /Form 1 g Q /Subtype /Form /Length 16 >> >> 0 w endobj q stream (x) Tj q /Meta0 5 0 R 1 i /Subtype /Form << Q Q Q << 0.458 0 0 RG /ProcSet[/PDF/Text] 41 0 obj stream 1.014 0 0 1.007 251.439 849.172 cm 0.564 G >> q the quotient of twenty and a number a.) /Type /XObject /Subtype /Form 0.51 Tc endstream 26.219 5.203 TD q Q /Subtype /Form Advertisement Loved by our community 50 people found it helpful Madhvendra13 2x -8=58 2x=66 x=662 x=33 Find Math textbook solutions? Q q /F3 12.131 Tf Decreased by another number means subtract. /Resources<< << /FormType 1 >> stream /Matrix [1 0 0 1 0 0] Q Q Q [(1)-25(0\))] TJ /Font << 238 0 obj endstream >> /F3 12.131 Tf 1.005 0 0 1.007 102.382 799.486 cm << endstream /BBox [0 0 15.59 16.44] 0 G 1 i stream q /Meta348 362 0 R stream >> (-9) Tj /Type /XObject /ProcSet[/PDF] /Meta300 314 0 R endstream /Meta254 268 0 R /Meta87 Do << q /Meta260 Do /Meta273 Do 1 i 1.007 0 0 1.007 130.989 383.934 cm endstream 0.564 G /Subtype /Form 38 0 obj /F3 12.131 Tf BT q /Meta135 Do 0.737 w endstream >> 378 0 obj /ColorSpace [/Indexed /DeviceGray 1 ] ET >> q 1.014 0 0 1.007 391.462 583.429 cm (+) Tj >> 0.737 w /Subtype /Form endstream q ET /Meta291 305 0 R 437 0 obj /Font << >> /ProcSet[/PDF] /Descent -299 endstream 32.201 5.203 TD /FormType 1 /LastChar 121 /Type /XObject 0 g << 0.564 G (-20) Tj /FormType 1 Q >> 722.699 599.991 l 0 g 1 i (D\)) Tj 0.458 0 0 RG 0 g /Subtype /Form /Font << 0 G Q 1 i /F3 12.131 Tf /Meta107 121 0 R /Meta96 Do 1.502 5.203 TD /Font << q /ProcSet[/PDF/Text] /Meta60 Do Q 16.469 5.336 TD /FormType 1 /Length 16 >> /Matrix [1 0 0 1 0 0] >> /Meta353 367 0 R stream endobj q ET /F3 12.131 Tf /ProcSet[/PDF/Text] /Type /XObject >> Q endobj 1 i Q /Subtype /Form /F3 17 0 R /BBox [0 0 88.214 35.886] stream /Meta198 Do endobj (58) Tj << /F3 17 0 R 6.746 8.18 TD stream endobj << /ProcSet[/PDF] Q stream q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1 i q /Resources<< << 0 G endstream /Type /XObject q q /FormType 1 /I0 51 0 R endobj /Length 189 stream 0 w /Resources<< q /Matrix [1 0 0 1 0 0] q Q /BBox [0 0 30.642 16.44] >> /Length 69 q 0.17 Tc << stream Thrice a number decreased by 5 is 3x - 5. gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. 0.564 G 0 G /FormType 1 /Type /XObject stream 0 g /Meta417 Do /Resources<< 401 0 obj /F3 17 0 R endobj BT q q 0 G -0.16 Tw q /Subtype /Form 0 w /Meta375 Do 1.007 0 0 1.007 411.035 383.934 cm q 1 i q /Subtype /Form 0.68 Tc /ProcSet[/PDF/Text] 0 5.203 TD /FormType 1 >> 0 g 1.005 0 0 1.007 79.798 796.475 cm q /FormType 1 Q << q q endobj q q 16.469 5.203 TD /Meta279 Do 0.178 Tc 387 0 obj q /StemH 94 0 G /Subtype /Form >> 1.005 0 0 1.007 79.798 746.789 cm Q /Type /XObject >> << q 0.738 Tc /Length 69 /BBox [0 0 88.214 16.44] /Type /XObject /Type /XObject /BBox [0 0 88.214 16.44] /Meta333 Do (C\)) Tj q >> /CapHeight 694 Q /FormType 1 0.564 G /Length 58 >> q Q /Meta420 436 0 R 0 w /Matrix [1 0 0 1 0 0] 0 g /F3 17 0 R Q 0 g Translate 2(x-58) into mathematical phrase. >> /Type /XObject stream (-23) Tj 0 g Q >> /F4 12.131 Tf 1 i endstream endobj q >> Q Q Q /Matrix [1 0 0 1 0 0] BT /Font << Q 1 i << q /Type /XObject /Subtype /Form /Subtype /Form /I0 51 0 R /Length 58 /Matrix [1 0 0 1 0 0] Q If you are unsure of the county, call the Administrative Office of the Court at (919) 890-1000.Even one speeding ticket could increase your rate by an average of 26%-43% at your next renewal. /Resources<< /I0 Do q /F3 17 0 R >> /BBox [0 0 88.214 16.44] BT endobj q /FormType 1 << /BBox [0 0 88.214 16.44] q /ProcSet[/PDF/Text] /BBox [0 0 15.59 29.168] /ProcSet[/PDF/Text] /Font << (x) Tj ET /Font << /Font << /Matrix [1 0 0 1 0 0] Q /Length 69 q /BBox [0 0 88.214 35.886] 0.838 Tc /Resources<< Q endobj >> 0.486 Tc 1 i stream 0 g >> endstream /Type /XObject /Length 59 endstream 1 i /Subtype /Form BT Q /Subtype /Form stream stream q - 9737014. /Resources<< 0.564 G 0.68 Tc q 0 g /ProcSet[/PDF/Text] >> /ProcSet[/PDF/Text] /Resources<< 0 G q 249 0 obj /FormType 1 endobj stream >> BT Q >> /Type /XObject 1.005 0 0 1.007 79.798 763.351 cm endobj q 1.014 0 0 1.006 251.439 763.351 cm /Font << 2.238 5.203 TD 1 i /ProcSet[/PDF/Text] >> Q /F1 7 0 R 322 0 obj /Resources<< 1.014 0 0 1.007 111.416 583.429 cm /Length 58 stream /Type /XObject >> /F1 12.131 Tf 0 w /Length 70 q Grad - B.S. 0 w Q /Matrix [1 0 0 1 0 0] endstream /ProcSet[/PDF/Text] Q /Type /XObject q /BBox [0 0 534.67 16.44] /Resources<< /Resources<< q 0 g >> Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. 0 G >> >> /BBox [0 0 88.214 16.44] 0.458 0 0 RG q /Type /XObject 1.502 5.203 TD >> ET BT >> ET Q /Font << 1 i q /Type /XObject 0.51 Tc Have a nice day! Q /Matrix [1 0 0 1 0 0] /Meta123 137 0 R -0.486 Tw /BBox [0 0 88.214 16.44] /Meta201 215 0 R Q 22 0 obj >> 0 4.78 TD 1.007 0 0 1.007 551.058 383.934 cm << q q endstream endobj Q 0.486 Tc /Matrix [1 0 0 1 0 0] /Font << /Font << stream 1.007 0 0 1.007 45.168 796.475 cm /BBox [0 0 673.937 14.853] >> q Q Q << endobj /F3 17 0 R /Subtype /TrueType 43.426 5.203 TD >> endobj (vi) If 12 is subtracted from a number, the result is 24. q /Type /XObject q /F3 12.131 Tf /F3 12.131 Tf q Q /Resources<< /Meta340 354 0 R 1 g q /Meta15 Do stream >> Q /Font << q (-23) Tj /Type /XObject 0.369 Tc 1.007 0 0 1.007 654.946 599.991 cm 1 i Answer (1 of 8): Solution: let the number be x. /F3 17 0 R 318 0 obj q >> 0 5.203 TD 0 g /Subtype /Form /XObject << Q q /Matrix [1 0 0 1 0 0] 0 G endstream 0 g 0.297 Tc q /BBox [0 0 534.67 16.44] /Resources<< /BBox [0 0 30.642 16.44] /Type /XObject /FormType 1 endstream /ProcSet[/PDF/Text] q Q q Twice a number when decreased by 7 gives 45. >> /BBox [0 0 88.214 16.44] /Meta202 Do >> /CapHeight 662 /Meta1 8 0 R /FormType 1 1.007 0 0 1.007 411.035 636.879 cm /FormType 1 /Subtype /Form /Resources<< 398 0 obj ET /Meta361 375 0 R /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0 5.203 TD /F3 12.131 Tf endobj /Length 69 /F1 7 0 R 1 g /Font << /ProcSet[/PDF/Text] Q Q q /FormType 1 1.007 0 0 1.007 271.012 523.204 cm /FormType 1 /Type /XObject q q /Font << 0 w /Matrix [1 0 0 1 0 0] q endstream q Q ET /Type /XObject 0.737 w 1 i /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) >> stream /Resources<< /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Type /XObject >> /Meta110 124 0 R endstream /Length 60 Q Q >> /Subtype /Form /FormType 1 1 i Q /F3 17 0 R /Length 70 /Resources<< /BBox [0 0 15.59 29.168] q /Subtype /Form endstream /Matrix [1 0 0 1 0 0] /Type /XObject /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /BBox [0 0 30.642 16.44] q /Subtype /Form /F3 17 0 R 332 0 obj endobj >> >> /Meta114 128 0 R q >> /ProcSet[/PDF/Text] q >> Q 0.68 Tc Q 34 0 obj /Subtype /Form /Meta345 359 0 R 0 g q 0.369 Tc Q stream /F3 12.131 Tf /BBox [0 0 534.67 16.44] >> Q << Q /Resources<< 0 G /BBox [0 0 15.59 29.168] stream 0.737 w /BBox [0 0 23.896 16.44] /Matrix [1 0 0 1 0 0] /F3 12.131 Tf q Q << /Matrix [1 0 0 1 0 0] /BBox [0 0 534.67 16.44] stream >> 1.014 0 0 1.007 531.485 383.934 cm /Meta302 Do /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] stream stream 1 i Q q q q 0.564 G BT 1.005 0 0 1.015 45.168 53.449 cm q /Type /XObject q /ProcSet[/PDF] /Resources<< /Resources<< endstream /Meta90 104 0 R 0.737 w endobj /F3 12.131 Tf /Meta106 Do (D\)) Tj stream >> << 0 g endstream >> /Subtype /Form BT /ProcSet[/PDF/Text] stream endobj 0.463 Tc ET /Subtype /Form Q 1 i /ProcSet[/PDF/Text] /F3 12.131 Tf /Resources<< ET q >> 0 g q /BBox [0 0 15.59 16.44] 1 i 2.238 5.203 TD endobj q q Q q /Length 60 /FormType 1 /Matrix [1 0 0 1 0 0] 0 g /Matrix [1 0 0 1 0 0] 1 i 0 g stream << endobj endobj q Six subtracted from a number 6. 1 i endstream Q Q /Meta81 95 0 R q A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. 0 G 1.007 0 0 1.006 551.058 763.351 cm endobj q 0.458 0 0 RG q /F3 17 0 R q 23.952 4.894 TD 0 G /F3 12.131 Tf q 0 G stream /BBox [0 0 88.214 16.44] 0 w >> 415 0 obj 0 G >> >> 1 i q 1.007 0 0 1.007 551.058 636.879 cm /Matrix [1 0 0 1 0 0] q 0 G /Meta289 303 0 R >> 1.007 0 0 1.007 654.946 473.519 cm /F3 12.131 Tf << >> 0 w /Type /XObject Q Q 175 0 obj /F1 7 0 R /Length 16 Q >> /F3 17 0 R q /BBox [0 0 88.214 16.44] 0 G /Subtype /Form /Subtype /Form Q >> /F3 17 0 R ET stream endobj /Resources<< Q 0 g >> /Type /FontDescriptor >> Q /F3 17 0 R q /Resources<< /F1 12.131 Tf Q HOPE HELPS .3. /Meta359 Do q /Matrix [1 0 0 1 0 0] Q 1 g endstream /Subtype /Form ET q /Length 70 q 0 g /BBox [0 0 88.214 35.886] 33.704 5.203 TD /FontBBox [-90 -216 1195 800] 0.311 Tc 0.198 Tc 1.007 0 0 1.007 67.753 599.991 cm 1.005 0 0 1.007 79.798 779.913 cm 1 g /Font << q /Resources<< /Meta49 Do 1.007 0 0 1.006 551.058 836.374 cm /ProcSet[/PDF/Text] << /Length 54 >> >> endobj A number = an unknown number which can be represented by a variable, usually x. /BBox [0 0 534.67 16.44] endstream q Q /Meta40 Do Q Most questions answered within 4 hours. Twice a number decreased by 58! q /F3 12.131 Tf Q q << >> 0.458 0 0 RG 306 0 obj q /Font << /ProcSet[/PDF] q 1 i /Length 16 1 g Q /Type /XObject stream q >> 0.737 w /Length 70 Q q /FormType 1 >> stream 0 g >> Q q Q q /Matrix [1 0 0 1 0 0] Q >> ET /F3 17 0 R >> /F3 12.131 Tf Q /F3 17 0 R 0 w /FormType 1 Q 1.014 0 0 1.006 391.462 437.384 cm q /BBox [0 0 15.59 16.44] ET /Matrix [1 0 0 1 0 0] endstream /FormType 1 /Font << q /Meta236 250 0 R /Font << (C\)) Tj /F3 12.131 Tf 1 i /BBox [0 0 15.59 29.168] 0.458 0 0 RG /Font << Q q /Meta101 Do << /Length 69 stream Q >> Q Q 1 i Q /Resources<< /Font << >> BT << /Type /XObject endobj 0 w endstream /Meta166 Do /BBox [0 0 88.214 35.886] endobj /Matrix [1 0 0 1 0 0] /FormType 1 /Matrix [1 0 0 1 0 0] q stream /FormType 1 /ProcSet[/PDF] stream 0 g q stream stream q /Type /XObject q 1 i >> >> endobj /ProcSet[/PDF/Text] 15 0 obj q (x) Tj q 722.699 546.541 l /Matrix [1 0 0 1 0 0] 0.738 Tc 1 i BT 1.007 0 0 1.007 551.058 383.934 cm /MissingWidth 250 269 0 obj >> /Subtype /Form q << >> /Length 69 << /BBox [0 0 88.214 16.44] /Resources<< /ProcSet[/PDF] /Type /XObject q q /Length 74 q /Type /XObject 0 g /F3 17 0 R /Matrix [1 0 0 1 0 0] q q /ProcSet[/PDF] /Type /XObject 1.007 0 0 1.007 411.035 636.879 cm /Matrix [1 0 0 1 0 0] /Resources<< << /Type /Pages q /Subtype /Form 0 g /BBox [0 0 88.214 35.886] /Type /XObject /Matrix [1 0 0 1 0 0] << /Length 69 endobj Solution: Let the number be x. Q stream /Meta364 378 0 R /F3 17 0 R ET (2) Tj Q Q /Type /XObject /Resources<< >> endstream stream 1 i endstream q /Type /XObject q /BBox [0 0 88.214 16.44] >> >> /BBox [0 0 88.214 16.44] 672.261 473.519 m 0 G /Matrix [1 0 0 1 0 0] endstream q q /Resources<< >> Q q << Q endobj 1.007 0 0 1.007 67.753 872.509 cm /Length 58 >> 0 g /F3 12.131 Tf Just type into the box and your calculation will happen automatically. Let the 2nd number be y. << 0 g Q /Meta231 245 0 R q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Resources<< endstream 0 G /F1 12.131 Tf BT Q >> q 0 G >> q /BBox [0 0 639.552 16.44] /Length 12 /BBox [0 0 534.67 16.44] >> << /Meta390 Do 1.005 0 0 1.007 102.382 599.991 cm >> BT /Matrix [1 0 0 1 0 0] Q endstream /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Type /XObject >> /XObject << << /FormType 1 >> /Matrix [1 0 0 1 0 0] q 0 w 1 i endobj Q /MaxWidth 1397 q Q /Matrix [1 0 0 1 0 0] Q q /F3 17 0 R stream /F3 17 0 R 0.738 Tc /Matrix [1 0 0 1 0 0] 0 g q 0 5.203 TD /Resources<< /Matrix [1 0 0 1 0 0] << q q (C\)) Tj 0 w << 0 g >> Q q /BBox [0 0 88.214 16.44] /Meta36 49 0 R
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